Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were in the group?

Answer:5Step-by-step explanation:You need to set up and solve a system of linear equations here.Let s and a represent the number of students and adults respectively.Then s + a = 9, and s = 9 - a.Total ticket cost for the adults was ($8/adult)(a)and for the students ($5/student)(s).Total cost of the tickets was then  ($8/adult)(a) + ($5/student)(s) = $60.Then our system of linear equations is:8a + 5s = 60  a  +  s  = 9, or s = 9 - a.  Substituting 9 - a for s, we get:8a + 5(9 - a) = 60.Then 8a + 45 - 5a = 60, or 3a = 15.Solving for a, we get a = 5.Solving for s using s = 9 - a, we get   s = 9 - 5, or s = 4.There were 5 adults in the group (and 4 students).