Find three consecutive intergers such that the sum of twice the smallest and 3 times the largest is 126
Accepted Solution
A:
Answer:Answer:
24
,
25
,
26Step-by-step explanation:Let's call the smallest integer n
. Then the next two consecutive integers are n
+
1
and n
+
2
.
"Sum of twice the smallest and 3 times the largest is 126"
2
(
n
)
+
3
(
n
+
2
)
=
126
2
n
+
3
n
+
6
=
126
5
n
+
6
=
126
5
n
=
120
n
=
24
So the smallest integer is 24
.
The three consecutive integers are then: 24
, 25
, and 26
.