Let a be directly proportional to m and n^2, and inversely proportional to y^3. If a=4 when m=9, n=4, and y=2, find a when m=7, n=3, and y=5.a=? (Type an integer or a simplified fraction.)
Accepted Solution
A:
Answer:4Step-by-step explanation:Step 1Let a be directly proportional to m and n^2a [tex]\alpha[/tex] m(n)²a = km(n)²Step 2Let a be inversely proportional to y^3a [tex]\alpha[/tex] [tex]\frac{1}{y^{3} }[/tex]a = [tex]\frac{k}{y^{3} }[/tex]Step 3 Plug values in the equation to find k4 = k (9)(4)²/2³4 = k 144 / 8 4 = 18kk = 4/18k = 2/9Step 4find aa = (2/9)(9)(4)²/2³ = 32 / 8 = 4