A projectile is shot into the air following the path, h(x) = -3x2 + 30x + 300. What will its maximum height reach?

Answer:375 unitsStep-by-step explanation:"What will its maximum height be?"The given equation, h(x) = -3x^2 + 30x + 300, is a quadratic with coefficients a = -3, b = 30 and c = 300.The axis of symmetry of this parabola will go thru the max ht.  The equation of the axis of symmetry isx = -b / (2a)In this particular case, the axis of symm. is x = -(30) / (2·[-3]), or x = 5 time units.The max height is thus h(5) = -3(5)^2 + 30(5) + 300 = 375 units.